ug二次开发中怎样实现移动已知名称的实体
发布网友
发布时间：2022-04-23 02:09
共3个回答
热心网友
时间：2023-09-18 03:01
源代码：0 F, I- m( ?4 p; O K; ?
entity/a1(100),pt(100); z! Q2 H& C3 _3 }% j. V
9 s& M7 q; [" c' s( y
l1:& ^$ h! u g% t+ ?7 [# H
gpos/'选择一个点',x,y,z,resp$ H" f7 m2 i9 _$ W+ Z B
jump/l1:,end:,,,resp
l10:2 ~3 C2 s# {# E/ s2 q% G7 W3 ?
param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp
jump/l10:,end:,,,resp
l2:
a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,12 C0 e* C0 D2 X# H# v1 |! L" c' \3 D
a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-1
a1(4)=unite/a1(1),with,a1(2)
a1(5)=unite/a1(3),with,a1(4)
a1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-1/ U7 D( c- W4 Y5 I9 x' }
a1(7)=unite/a1(5),with,a1(6)/ U* e+ u, L% L. f
pt(1)=point/x+11.53,y,z-30
blend/a1(7),chamfr,14,pt(1)
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1
a1(9)=unite/a1(7),with,a1(8)4 @6 O- h1 E. e' ~* q0 p- X9 W
a1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,70/ m. D8 C% w4 T: f. P7 [
a1(11)=subtra/a1(9),with,a1(10)5 l& p( L2 k+ p9 I1 R e% F
pt(2)=point/x+35,y,z-22.67767
blend/a1(11),chamfr,17.32233,pt(2)
a1(12)=solsph/origin,x,y,z-5,diamtr,50
a1(13)=subtra/a1(11),with,a1(12)
a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.3009
a1(15)=subtra/a1(13),with,a1(14)
pt(3)=point/x,y+49.9,z+10
blend/a1(15),chamfr,0.5,pt(3)
pt(4)=point/x,y+62.5,z9 {$ X0 E. ]; I4 ^6 B. A
blend/a1(15),chamfr,0.5,pt(4); b( K! [0 z5 J
pt(5)=point/x,y+62.5,z-155 [2 Q+ V0 x; [$ {
blend/a1(15),chamfr,0.5,pt(5)
pt(6)=point/x,y+50,z-30$ v P( O$ M* j
blend/a1(15),chamfr,0.5,pt(6)
pt(7)=point/x,y+35,z+10
blend/a1(15),chamfr,0.5,pt(7)
delete/pt(1..100): u# h( s: [8 P6 u
a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-17 @3 {* d( Q. Y6 f1 O
a1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-1
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-17 l1 g, |: m7 ?3 A& f0 E9 b
a1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-19 o$ C' ~8 s+ s9 Q. H: p6 d8 r& H
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1% J6 f3 }) V8 p! L) ?5 E& z
a1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1; `' o0 i M) _1 R+ r
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
a1(24)=subtra/a1(15),with,a1(16)
a1(25)=subtra/a1(24),with,a1(17)
a1(26)=subtra/a1(25),with,a1(18)& o9 ]- X: A5 O' g" b7 h* l8 q: k; U
a1(27)=subtra/a1(26),with,a1(19)
a1(28)=subtra/a1(27),with,a1(20)
a1(29)=subtra/a1(28),with,a1(21)
a1(30)=subtra/a1(29),with,a1(22)! c' f0 H! L \
a1(31)=subtra/a1(30),with,a1(23)4 X+ Q! Y7 d; q H+ z
&color(a1(31))=1216 y5 [/ y8 L1 V
&name(a1(31))='JZ'7 l/ m% F% n$ a+ S' ?6 z
jump/l1:" d. ?: N6 x8 X5 q, z/ x
end:
halt
热心网友
时间：2023-09-18 03:01
UG二次开发不容易的，需要投放大量的时间和精力！多去翻译下UG的API帮助文档，当初我在做UG二次开发时，也和你的情况一样，二次开发需要自己领悟，总之想要的功能一定会开发出来的，只不过是时间问题罢了。
热心网友
时间：2023-09-18 03:03
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